That will be the number of solutions.
So in this situation there is no solutions, or no real-- when I say real I literally mean a real number-- no real solution. We could just apply the quadratic formula. Then we add to both sides to get b alone. Since you can't find a graphable solution to the quadratic, then reasonably there should not be any x-intercepts because you can graph an x-intercept.
And negative b is-- we could just solve it. So this right here is So if b squared minus 4ac is equal to 0, you only have one solution. Now what happens if b squared minus 4ac is equal to 0?
The square root of b squared is b, and the square root of is