# Write a quadratic equation with only one solution

That will be the number of solutions.

So in this situation there is no solutions, or no real-- when I say real I literally mean a real number-- no real solution. So 49 times 4. You're only going to have one solution. So b squared minus 4ac is minus It's going to have a square root. Using that information, and since we know a and c, we can find our b. The square root of b squared is b, and the square root of is

So in this situation there is no solutions, or no real-- when I say real I literally mean a real number-- no real solution. We could just apply the quadratic formula. Then we add to both sides to get b alone. Since you can't find a graphable solution to the quadratic, then reasonably there should not be any x-intercepts because you can graph an x-intercept. And negative b is-- we could just solve it. So this right here is So if b squared minus 4ac is equal to 0, you only have one solution. Now what happens if b squared minus 4ac is equal to 0? The square root of b squared is b, and the square root of is

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